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0=4x^2+18x-252
We move all terms to the left:
0-(4x^2+18x-252)=0
We add all the numbers together, and all the variables
-(4x^2+18x-252)=0
We get rid of parentheses
-4x^2-18x+252=0
a = -4; b = -18; c = +252;
Δ = b2-4ac
Δ = -182-4·(-4)·252
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-66}{2*-4}=\frac{-48}{-8} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+66}{2*-4}=\frac{84}{-8} =-10+1/2 $
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